905.60 The Disequilibrium 120 LCD Triangle
905.61 The icosahedral spherical great-circle system displays:
12 vertexes surrounded by 10 converging angles;
20 vertexes surrounded by 6 converging angles;
30 vertexes surrounded by 4 converging angles
12 x 10 = 120
20x6 =120
30x4 =120
360 converging angle sinuses.
905.62 According to the Principle of Angular Topology (see Sec. 224), the 360 converging angle sinuses must share a 720-degree reduction from an absolute sphere to a chorded sphere:
905.63 In subsiding the 120 spherical triangles generated by the 15 great circles of the icosahedron from an omnispherical condition to a neospheric 120-planar-faceted polyhedron, we produce a condition where all the vertexes are equidistant from the same center and all of the edges are chords of the same spherical triangle, each edge having been shrunk from its previous arc length to the chord lengths without changing the central angles. In this condition the spherical excess of 6 degrees could be shared proportionately by the 90, 60, 30flat triangle relationship which factors exactly to
905.64 Alternatively, the spherical excess of 6 degrees (one quantum) may be apportioned totally to the biggest and littlest corners of the triangle, leaving the 60-degree, vector equilibrium, neutral corner undisturbed. As we have discovered in the isotropic vector matrix nature coordinates crystallographically in 60 degrees and not in 90 degrees. Sixty degrees is the vector equilibrium neutral angle relative to which life-in-time aberrates.
Basic Draftsman’s Triangle (Flat) (minus 5) = 30
Flatout >1 Quanta
*Module Triangle *
*35
60
84
180
(unchanged) = 60
(plus 5) = 90
180
905.65 By freezing the 60-degree center of the icosahedral triangle, and by sharing the 6-degree, spherical-planar, excess reduction between the 36-degree and 90-degree corners, we will find that the
image
Table 905.65
905.66 The Earth crust-fault angles, steel plate fractionation angles, and ship’s bow waves all are roughly the same, reading approximately 70-degree and 110-degree complementation.
Dihedral angle of octahedron = 109= 2 x 54
Dihedral angle of tetrahedron = 70
180
54
5
x 2–60
10
+ 54
109
If 5= unity; 54= 60- 1 quantum; and 70= 60+ 2 quanta.
Obviously, the 70and 109relate to the “twinkle angle” differential from 60(cosmic neutral) and to the 109central angle of the spherical tetrahedron. (See also Sec. 1051.20.)